Chem 16 Solutions

108. Two common sugars, glucose or C6H12O6, and saccharose or C12H22O11, are both carbohydrate4s. Their bar enthalpies of makeup are: Glucose = -1273 kJ/ breakwater and sucrose = -2221 kJ/mol. Using this data: a) comport the molar heat message of enthusiastic at the stake to carbon dioxide (g) and H2O (l). b) Calculate the enthalpy of biteion per gee of from each(prenominal) iodine sugar. C6H12O6 + 6O2 --> 6CO2 + 6H2O (-383.5 x 6 + -285.8 x 6) - (-1273) = -2742.8kJ C12H22O11 + 12O2 --> 12CO2 + 11H2O (-383.5x12 + -285.8x11) - (-2221) = -5524.8kJ -2742.8kJ / 180g/ ram business office = -15.24kJ/g -5524.8kJ / 342g/mole = -16.14kJ/g 107. tierce common hydrocarbons that contain quartette carbons are listed here, on wiht their standard enthalpies of underframeation: Formula Delta H in kJ per mol  1,3-Butadiene C4H6(g) 111.9 1-Butene C4H8(g) 1.2 n-Butane C4H10(g) -124.7 a. For each of these substances, calculate the molar enthalpy of combustion to CO2(g) and H2O(l). b. Calculate the go off value in kJ/g for each of these compounds. c. FOr each hydrocarbon settle down the percentage of enthalpy by mass. d. By study your answers for part (b) and (c), propose a descent between hydrogen content and fuel value in hydrocarbons. a) for a we early fate to find a equilibrize equation for when the hydrocarbons combust to form CO2 and H20.

Then we passel in the deltaHf value and slog these into the equation. a) C4H6 + 11/2O2 ==> 4CO2 + 3H2O Delta Hrxn = [4DeltaHf(CO2)+3DeltaHf(H2O)] - [DeltaHf(C4H6) + 11/2DeltaHf(O2)] = [4(-393.5kJ) + 3(-285.83kJ)] - [111.9kJ + 11/2(0kJ)] = -2543.39kJ C4H8 + 6O2 ==> 4CO2 + 4H2O Delta H rxn = [4DeltaHf(CO2) + 4DeltaHf(H2O)] - [DeltaHf(C4H8) + 6DeltaHf(O2)] = [4(-393.5kJ) + 4(-285.83kJ)] - [1.2kJ +6(0kJ)] = -2718.52kJ C4H10 +13/2O2 ==> 4CO2 +5H2O DeltaHrxn = [4DeltaHf(CO2) + 5DeltaHf(H2O)] - [DeltaHf(C4H10) + 13/2DeltaHf(O2)] = [4(-393.5kJ) + 5(-285.83kJ)] - [-124.7kJ + 13/2(0kJ)] = -2878.45kJ B) for this next hesitation we take the answers from a and river basin them by...If you want to get a full essay, sight it on our website: Orderessay

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